Question

SELECT CASE WHEN LEFT([HexData], 2) = '0x'
            THEN CONVERT(varchar(max), CONVERT(varbinary(MAX), [HexData], 1))
            ELSE CONVERT(varchar(max), CONVERT(varbinary(MAX), [HexData], 2))
       END
FROM tableName

ANGULARJS

**Unable to Route**
 <!DOCTYPE html>
<html lang="en" ng-app="mymodule">
<head>
<meta charset="UTF-8">
<title>Index</title>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.2/angular.min.js"> </script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.2/angular-route.js"></script>
<script src="angular-resource.min.js" type="text/javascript"></script>
<script src="app.js" type="text/javascript"></script></head>
<body>
<h1>Routing</h1>
 <a href="#/Course">Course</a>
 <a href="#/Students">Students</a>
 <div ng-view></div>
 </body>

https://i.stack.imgur.com/nG9rK.png

*我刚接触到角度，当我试图路由iam无法做到这一点时，它会抛出一个错误。如果有人能解决这个问题，我会真的很高兴。谢谢*

Answer 1

将tilUserName = (TextInputLayout) findViewById(R.id.userName_til); etUserName = (TextInputEditText) findViewById(R.id.etUserName); etUserName.addTextChangedListener(new TextWatcher() { @Override public void beforeTextChanged(CharSequence s, int start, int count, int after) { } @Override public void onTextChanged(CharSequence s, int start, int before, int count) { Timber.d("OnTextChanged Called"); if (s.length() < 1) { tilUserName.setErrorEnabled(true); tilUserName.setError(getString(R.string.please_enter_email_id)); } else if (!AppUtils.isValidEmail(s)) { tilUserName.setErrorEnabled(true); tilUserName.setError(getString(R.string.please_enter_valid_email_id)); } else { tilUserName.setError(null); tilUserName.setErrorEnabled(false); } } @Override public void afterTextChanged(Editable s) { } });的两个实例都更改为compile 'com.android.support:appcompat-v7:25.2.0' compile 'com.android.support:design:25.2.0'。 e.g。

$routeprovider

Answer 2

将$routeprovider重命名为$routeProvider。

请记住，在角度工作时，参数名称应与教师告诉您的完全相同（我认为它是w3schools）。

角度无法路线

2 个答案: