<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die('Error connecting to
mysql');
$dbname = 'vendordb';
mysql_select_db($dbname);
?>
<html>
<div class="row">
<form id="form1" name="form1" action="<?php $_SERVER['PHP_SELF'];?>"
method="post">
<?php
$result=mysql_query("select crtname from crtinfo");
echo "<select id='criteria1' name='criteria1'" . ">";
while($row = mysql_fetch_array($result))
{
echo "<option value=".$row[0]. ">". $row[0]. "</option>";
}
echo "</select>";
$crt1=$_POST['criteria1'];
echo $crt1;
?>
</form>
</div>
无法在$ _POST中获取下拉值
错误:
注意:未定义的索引:第25行的C:\ xampp \ htdocs \ website \ dropdowntest.php中的criteria1 无法从$ _POST获得价值
答案 0 :(得分:0)
试试这个:
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die('Error connecting to
mysql');
$dbname = 'vendordb';
mysql_select_db($dbname);
?>
<html>
<div class="row">
<form id="form1" name="form1" action="<?php $_SERVER['PHP_SELF'];?>"
method="post">
<?php
$result=mysql_query("select crtname from crtinfo");
echo "<select id='criteria1' name='criteria1'>";
while($row = mysql_fetch_assoc($result))
{
echo "<option value=".$row['crtname']. ">". $row['crtname']. "</option>";
}
echo "</select>";
?>
<input type="submit" name="submit" value="submit">
</form>
<?php
if(isset($_POST['criteria1'])){
echo $_POST['criteria1'];
}
?>
</div>
答案 1 :(得分:0)
虽然我不确定这是否会解决问题,但这是一个关于如何使用isset()
if(isset($_POST["critera"])
{
$crt1=$_POST['criteria1'];
echo $crt1;
}
答案 2 :(得分:0)
您无法获得帖子价值。试试这个:
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die('Error connecting to
mysql');
$dbname = 'vendordb';
mysql_select_db($dbname);
?>
<html>
<div class="row">
<form id="form1" name="form1" action="<?php $_SERVER['PHP_SELF'];?>"
method="post">
<?php
$result=mysql_query("select crtname from crtinfo");
echo "<select id=criteria1 name=criteria1" . ">";
while($row = mysql_fetch_array($result))
{
echo "<option value=".$row[0]. ">". $row[0]. "</option>";
}
echo "</select>";
?>
<input type="submit" value="submit">
</form>
<?php
if(isset($_POST['criteria1'])){
echo $_POST['criteria1'];
}
?>
?>
</div>
&#13;