Question

我在JSP中实现自定义404处理程序 - AEM，CQ。该文件位于apps / sling / servlet / errorhandler / 404.jsp

中

我正在使用RequestDispatcher类拦截Not Found和转发请求。

<%@taglib prefix="sling" uri="http://sling.apache.org/taglibs/sling"%>
<sling:defineObjects />
<%
    // setting response code as 404
    response.setStatus(HttpServletResponse.SC_NOT_FOUND);
response.setStatus(404);
System.out.println(response.getStatus());
        try {
            RequestDispatcher rd = request.getRequestDispatcher("/error-page.html");

            rd.forward(request, response);


        } catch (Exception e) {
            RequestDispatcher rd = request.getRequestDispatcher("/error-page.html");
            rd.forward(request, response);

        }

%>

以上代码获取error-page.html的内容，保持URL相同，但发回的响应代码不是404.而是200.

如何退回404？

Answer 1

使用#include而非#forward将允许您返回404：

response.setStatus(HttpServletResponse.SC_NOT_FOUND);
RequestDispatcher dispatcher = request.getRequestDispatcher(path);
dispatcher.include(request,response);

我建议创建Java Servlet而不是使用JSP：

@SlingServlet(metatype = true, resourceTypes = {"/apps/sling/servlet/errorhandler"}, extensions = {"404"})
public class ErrorServlet extends SlingSafeMethodsServlet {

    @Override
    protected void doGet(SlingHttpServletRequest request, SlingHttpServletResponse response) throws ServletException, IOException {
        response.setStatus(HttpServletResponse.SC_NOT_FOUND);
        RequestDispatcher dispatcher = request.getRequestDispatcher("myPath");
        dispatcher.include(request,response);
    }
}

您是直接在AEM中检查状态代码还是在Apache和Dispatcher之后检查？

使用请求调度程序JSP发送404

1 个答案: