Question

我正在尝试编写一个允许我从下拉列表中删除所选值的函数。

<?php
require_once("db.inc.php");
?>
</head>
<body>
<form action="" method="POST">
 <?php





$stmt = $mysqli->prepare("SELECT anr, name FROM artikel");
$stmt->execute();
$stmt->bind_result($anr, $name);


echo "<select name='selected_name'><br />";

while ($stmt->fetch()) {

echo '<option value='.$anr.'>'.$anr.' | '.$name.'</option>';


if(isset($_POST['loeschen'])){

    $stmt = $mysqli->prepare("DELETE FROM artikel WHERE anr=?");
        $stmt->bind_param('i', $anr);
        $stmt->execute();
        $stmt->close();
        $mysqli->close();

    }

}   


  ?>
  <input type="submit" value="Datensatz löschen" name="loeschen">
</form>
</body>
</html>

我的问题是，即使我没有按下提交按钮，也会删除这些值。提前感谢您的建议。

Answer 1

使用Post值而不是$ anr。

<?php
require_once("db.inc.php");
?>
</head>
<body>
<?php
if(isset($_POST['selected_name'])){

    $stmt = $mysqli->prepare("DELETE FROM artikel WHERE anr=?");
        $stmt->bind_param('i', $_POST['selected_name']);
        $stmt->execute();
        $stmt->close();
        $mysqli->close();

    }

}
?>
<form action="" method="POST">
 <?php

$stmt = $mysqli->prepare("SELECT anr, name FROM artikel");
$stmt->execute();
$stmt->bind_result($anr, $name);
echo "<select name='selected_name'><br />";
while ($stmt->fetch()) {
echo '<option value='.$anr.'>'.$anr.' | '.$name.'</option>';
}
echo "</select>";
  ?>
  <input type="submit" value="Datensatz löschen" name="loeschen">
</form>
</body>
</html>

Answer 2

唯一的错误是使用<{p>下面的$stmt->bind_param('i', $anr)而不是

   $stmt->bind_param('i', $_POST['selected_name']));

从下拉列表中删除值

2 个答案: