Question

我有一个像这样的TypeScript类：

它不是Angular模块
假设personName是自定义过滤器，在此示例中无法在视图/模板上使用

代码：

export class Person {
   private $filter;
   private name: string;
   private sureName: string;

   constructor($filter: ng.IFilterService, name: string, sureName: string) {
      this.$filter = $filter;
      this.name = name;
      this.sureName = sureName;
   }

   public getName(): string {
      return this.$filter('personName')(this.name, this.sureName);  
   }
}

这可以在控制器中使用，如下所示：

export class PeopleController {
   private $filter: ng.IFilterService;
   private person1 = new Person(this.$filter, 'Joe', 'Smith');
   private person2 = new Person(this.$filter, 'John', 'Doe');
   // ...
   // private person100 = new Person(this.$filter, ...)

   constructor($filter: ng.IFilterService) {
      this.$filter = $filter;
   }
}

angular.module('myApp').controller('PeopleController', PeopleController);

是否可以在没有Person的情况下重写$filter课程？换句话说，我可以使用依赖注入将Person类编写为Angular工厂，然后将此工厂注入控制器并创建实例吗？

我想要这样的事情：

export class PeopleController {
   private PersonFactory: Person;
   private person1 = new PersonFactory('Joe', 'Smith');
   private person2 = new PersonFactory('John', 'Doe');
   // ...
   // private person100 = new Person(...)

   constructor(PersonFactory: Person) {
      this.PersonFactory = PersonFactory;
   }
}

angular.module('myApp').factory('PeopleFactory', People);
angular.module('myApp').controller('PeopleController', PeopleController);

Answer 1

您可以创建一个工厂来注入 $ filter 服务并返回一个接受其余参数并返回人的函数

它看起来像这样。

interface PersonFactory {
    (name: string, surname: string): Person
}

angular.module('mymodule').factory('PersonFactory', function($filter: ng.IFilterService): PersonFactory {
    return function(name: string, surname: string): Person {
        return new Person($filter, name, surname);
    }
});

您将能够像这样使用它：

angular.module('myModule').controller('SomeCtrl', function(PersonFactory: PersonFactory) {
    let p = PersonFactory('John', 'Smith');
});

Angular 1和TypeScript：与类构造函数中的属性混合的依赖项

1 个答案: