Question

- (void)addRecordImageData:(NSData *)imageData x:(CGFloat)x y:(CGFloat)y cutterImageName:(NSString *)name
{
    NSInteger imageID = 0;
    if ([db open]) {
        NSString *sql = [NSString stringWithFormat:@"select id from imageName where name = '%@'",name];
        FMResultSet *result = [db executeQuery:sql];
        while ([result next]) {
            imageID = [result intForColumn:@"id"];
        }
        [db close];
    }
    if ([db open]) {
        NSString *sql = [NSString stringWithFormat:@"insert into imageData(nameid,data,x,y) values (%d,%@,%.f,%.f)",imageID,imageData,x,y];
        BOOL success = [db executeUpdate:sql];
        success ? NSLog(@"insert success") : NSLog(@"insert faulire");
        [db close];
    }
}

- (void)setUp:(UIImage*)cutterImage name:(NSString *)name
{
    CGImageRef imageRef = cutterImage.CGImage;
    totalColumns = ceilf(cutterImage.size.width / CUTWIDTH *1.0);
    totalRows = ceilf(cutterImage.size.height / CUTHEIGHT *1.0);
    NSInteger x=0,y=0;
    for (y = 0; y<totalRows; y++) {
        NSMutableArray *row = [NSMutableArray array];
        for (x = 0; x < totalColumns; x++) {
            CGFloat xOffset = x * CUTWIDTH;
            CGFloat yOffset = y * CUTHEIGHT;
            CGImageRef tileImageRef = CGImageCreateWithImageInRect(imageRef, CGRectMake(xOffset, yOffset, CUTWIDTH, CUTHEIGHT));
            NSData *imageData = UIImagePNGRepresentation([UIImage imageWithCGImage:tileImageRef]);
            
            [self.dataBase addRecordImageData:imageData x:xOffset y:yOffset cutterImageName:name];
        }
    }

}

这是我的代码，当我将数据插入数据库时，它始终是一个失败。我使用fmdb。当我运行程序时，自动跳转到fmdb中的一段代码。

Answer 1

我认为问题出在您的插入查询中。它应该有点像这样

@"insert into imageData(nameid,data,x,y) values (?,?,?,?)"

结帐this了解更多信息。

UIImagePNGRepresentation函数返回NSData类型，是否可以存储在SQLite中？

1 个答案: