这是需要解析的文本示例：
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line table (detailed)
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line
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if-index : 1/1/4/1 rel-cap-occ-up : 60 noise-margin-up : 165
output-power-down : 92 sig-attenuation-up : 32 loop-attenuation-up : 30
actual-opmode : g993-2-8d xtu-c-opmode : 00:00:00:00:00:00:00:00:48:00:00:00:00:00:00:00
ansi-t1413 : dis-ansi-t1413 etsi-dts : dis-etsi-dts g992-1-a : dis-g992-1-a
g992-1-b : dis-g992-1-b g992-2-a : dis-g992-2-a g992-3-a : dis-g992-3-a
g992-3-b : dis-g992-3-b g992-3-aj : dis-g992-3-aj g992-3-l1 : dis-g992-3-l1
g992-3-l2 : dis-g992-3-l2 g992-3-am : dis-g992-3-am g992-5-a : dis-g992-5-a
g992-5-b : dis-g992-5-b ansi-t1.424 : dis-ansi-t1.424 etsi-ts : dis-etsi-ts
itu-g993-1 : dis-itu-g993-1 ieee-802.3ah : dis-ieee-802.3ah g992-5-aj : dis-g992-5-aj
g992-5-am : dis-g992-5-am g993-2-8a : dis-g993-2-8a g993-2-8b : dis-g993-2-8b
g993-2-8c : dis-g993-2-8c g993-2-8d : g993-2-8d g993-2-12a : dis-g993-2-12a
g993-2-12b : dis-g993-2-12b g993-2-17a : g993-2-17a g993-2-30a : dis-g993-2-30a
actual-psd-down : -586 power-mgnt-state : l0
per-bnd-lp-att-up : 00:08:00:21:04:f6:04:f6:04:f6
pr-bnd-sgn-att-up : 04:f6:00:21:04:f6:04:f6:04:f6
pr-bnd-nois-mg-up : 02:76:00:a5:02:76:02:76:02:76 high-freq-up : 5197
elect-length : 3 time-adv-corr : -902 actual-tps-tc-mode : ptm
actual-ra-mode-up : automatic vect-cpe-type : legacy
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作为一个例子，我有以下模式来获取三个变量的值：
const string pattern1 = @"itu-g993-1[\s]{0,1}:[\s]{0,1}(?<itu_g993_1>.*?(?=\s))";
const string pattern2 = @"time-adv-corr[\s]{0,1}:[\s]{0,1}(?<time_adv_corr>.*?(?=\s))";
const string pattern3 = @"xtu-c-opmode[\s]{0,1}:[\s]{0,1}(?<xtu_c_opmode>.*?(?=\s))";
他们自己工作得很好。
我的问题是：
我之所以提出这个问题的原因是我们的要求仍然模糊不清，而且我们不确切知道我们需要提取哪些变量和多少变量。
答案 0 :(得分：1)
Because, it just finds it as it goes left to right,
you could just join them together using an alternation.
edit: If the regex's are dependent on a case by case basis,
you could always make a function that creates the full regex by
joining the individual ones (with alternation) based on a passed in bitmask.
This way you have a central place to store and manage all the individual regex.
string Lines =
@"
if-index : 1/1/4/1 rel-cap-occ-up : 60 noise-margin-up : 165
output-power-down : 92 sig-attenuation-up : 32 loop-attenuation-up : 30
actual-opmode : g993-2-8d xtu-c-opmode : 00:00:00:00:00:00:00:00:48:00:00:00:00:00:00:00
ansi-t1413 : dis-ansi-t1413 etsi-dts : dis-etsi-dts g992-1-a : dis-g992-1-a
g992-1-b : dis-g992-1-b g992-2-a : dis-g992-2-a g992-3-a : dis-g992-3-a
g992-3-b : dis-g992-3-b g992-3-aj : dis-g992-3-aj g992-3-l1 : dis-g992-3-l1
g992-3-l2 : dis-g992-3-l2 g992-3-am : dis-g992-3-am g992-5-a : dis-g992-5-a
g992-5-b : dis-g992-5-b ansi-t1.424 : dis-ansi-t1.424 etsi-ts : dis-etsi-ts
itu-g993-1 : dis-itu-g993-1 ieee-802.3ah : dis-ieee-802.3ah g992-5-aj : dis-g992-5-aj
g992-5-am : dis-g992-5-am g993-2-8a : dis-g993-2-8a g993-2-8b : dis-g993-2-8b
g993-2-8c : dis-g993-2-8c g993-2-8d : g993-2-8d g993-2-12a : dis-g993-2-12a
g993-2-12b : dis-g993-2-12b g993-2-17a : g993-2-17a g993-2-30a : dis-g993-2-30a
actual-psd-down : -586 power-mgnt-state : l0
per-bnd-lp-att-up : 00:08:00:21:04:f6:04:f6:04:f6
pr-bnd-sgn-att-up : 04:f6:00:21:04:f6:04:f6:04:f6
pr-bnd-nois-mg-up : 02:76:00:a5:02:76:02:76:02:76 high-freq-up : 5197
elect-length : 3 time-adv-corr : -902 actual-tps-tc-mode : ptm
actual-ra-mode-up : automatic vect-cpe-type : legacy
";
Regex RxData = new Regex(
@"
itu-g993-1[\s]{0,1}:[\s]{0,1}(?<itu_g993_1>.*?(?=\s))
| time-adv-corr[\s]{0,1}:[\s]{0,1}(?<time_adv_corr>.*?(?=\s))
| xtu-c-opmode[\s]{0,1}:[\s]{0,1}(?<xtu_c_opmode>.*?(?=\s))
", RegexOptions.IgnorePatternWhitespace );
Match _mData = RxData.Match( Lines );
while (_mData.Success)
{
if (_mData.Groups["itu_g993_1"].Success )
Console.WriteLine("itu_g993_1 = {0} \r\n", _mData.Groups["itu_g993_1"].Value);
if (_mData.Groups["time_adv_corr"].Success)
Console.WriteLine("time_adv_corr = {0} \r\n", _mData.Groups["time_adv_corr"].Value);
if (_mData.Groups["xtu_c_opmode"].Success)
Console.WriteLine("xtu_c_opmode = {0} \r\n", _mData.Groups["xtu_c_opmode"].Value);
_mData = _mData.NextMatch();
}
Output
xtu_c_opmode = 00:00:00:00:00:00:00:00:48:00:00:00:00:00:00:00
itu_g993_1 = dis-itu-g993-1
time_adv_corr = -902
答案 1 :(得分：1)
如果这些值始终存在，您可以在正向预测和以下正则表达式中使用捕获组：
(?s)^(?=.*itu-g993-1\s?:\s?(?<itu>\S*))(?=.*time-adv-corr\s?:\s?(?<time>\S*))(?=.*xtu-c-opmode\s?:\s?(?<xtu>\S*))
您可以在regexstorm.net进行测试。
即使环顾四周不消耗文本，文本本身也可以被捕获到组中，这在我们不需要匹配的情况下很有用，但只是一段文本。
请注意，正面预测需要模式以匹配子字符串，因此如果没有xtu-c-opmode，但itu-g993-1和time-adv-corr是，那么将不会匹配，也没有被捕获的组。