错误C3861:即使函数在标题中也找不到'decrypt'

时间:2014-04-19 01:38:11

标签: c++ visual-studio compiler-errors runtime-error

我加载了一个加密文本文件的代码,该文本文件的第一行是一个密码,用于解码文本文件的其余部分。我知道如果函数没有在main之前定义,通常会发生这个错误,但我在头文件中定义了它,所以我不确定是什么导致了这个问题。

#include <string>
#include <iostream>
#include <fstream> 

std::string decrypt(std::string cipher, std::string text);

int main()
{
//variable
std::string fileName; 
std::string cipher; 
std::string text;   

//prompt the user to enter the file name
std::cout << "Enter file name: "; 
std::cin  >> fileName;

//declare input stream
std::ifstream inFile(fileName); 

//Checks if the file has been connected or not
if (inFile.is_open()) 
{ 
    std::cout << "File found." << std::endl; 
    std::cout << "Processing..." << std::endl; 

    getline(inFile,cipher); //get the first line as one string
    std::cout << cipher << std::endl;  //TEST!!!!
    std::cout << "\n" << std::endl; //TEST!!!!!!

    while (inFile.good()) //continue running until an error occurs to get the rest of the text as second string
    {
        getline(inFile,text); //get the first line as one string
        std::cout << text << std::endl; //TEST!!!!
    }       
} 
else //if the file isn't connected
{ 
    std::cout << "File not found." << std::endl;    **(ERROR C3861 HERE)**
}

inFile.close(); //close the file

std::string finalResult = decrypt(cipher,text);
std:: cout << finalResult << std::endl;

return 0;
}

//Decrypt function: Takes 2 strings by reference, changes the second string into the    unencrypted text
std::string decrypt(std::string cipher, std::string text)
{

char alphabet[27] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; //create a character array of the alphabet 
char code[27]; //empty array 
char oldText[500]; //empty array 
strcpy(code,cipher.c_str()); //copies the cipher into the array
strcpy(oldText,text.c_str()); //copies the encrypted text into the array

for (int i = 0; i < 500;i++) //Loop through the entire encrypted text
{
    int k = i; //creates and resets a variable for while loop
    while (alphabet[k] != oldText[i])
    {
        k = k+1; 
    }
    oldText[i] = alphabet[k]; //after a match is detected, swap the letters
}

std::string newText(oldText); // converts the array back into text
return newText;
}

1 个答案:

答案 0 :(得分:1)

您的问题是decrypt中的这一行:

 std::string text(oldText); // converts the array back into text

它不会转换旧文字&#39;回到text;相反,它声明了一个名为test的新局部变量。新的局部变量与名为text的参数冲突。这是导致C2082的行。你应该写的是:

text = oldText;

test中的内容替换oldText的内容虽然完全跳过return oldText会更简单。

在编写代码时我没有C3861,而且你在错误的行显示C2082这一事实让我觉得你的源文件与你的源代码不同步错误。