Question

我有一个患者入院和出院日期的数据框（df），有4列：

ID，admitDate（作为日期），dcDate（作为日期），los（逗留时间）天）。

$ admitDate  : Date, format: "2009-09-19" "2010-01-24" "2010-09-30" ...
$ dcDate     : Date, format: "2009-09-23" "2010-01-27" "2010-10-04" ...
$ los        : num  4 3 4 25 6 3 6 2 2 3 ...

我需要能够在任何特定时间告诉患者（以及哪些患者）入院。也就是说，我想我需要找出患者之间的重叠情况。洛杉矶。以下是我定义重叠的方法：（df $ admitDate [x]＆lt; = df $ disDate [y]）＆amp; （df $ admitDate [y]＆lt; = df $ disDate [x]）

非常感谢任何帮助。

以下是前20位患者的输出结果：

> dput(head(df,20))
structure(list(Unit.Number = c(2013459L, 2013459L, 2047815L, 
1362858L, 1331174L, 2068040L, 1363711L, 2175972L, 2036695L, 1426614L, 
1403126L, 2083126L, 1334063L, 1349385L, 1404482L, 2175545L, 1296600L, 
1293220L, 1336768L, 2148401L), admitDate = structure(c(14506, 
14633, 14882, 15172, 14945, 15632, 15482, 15601, 16096, 15843, 
16013, 15548, 15436, 15605, 16115, 15597, 15111, 15050, 15500, 
15896), class = "Date"), dcDate = structure(c(14510, 14636, 14886, 
15197, 14951, 15635, 15488, 15603, 16098, 15846, 16016, 15552, 
15438, 15606, 16118, 15598, 15113, 15058, 15501, 15915), class = "Date"), 
los = c(4, 3, 4, 25, 6, 3, 6, 2, 2, 3, 3, 4, 2, 1, 3, 1, 
2, 8, 1, 19)), .Names = c("Unit.Number", "admitDate", "dcDate", 
"los"), row.names = c(NA, 20L), class = "data.frame")

首先，我尝试了G. Grothendieck建议的代码：

days <- seq(min(df$admitDate), max(df$dcDate), "day")
no.patients <- data.frame(
  Date = days, 
  Num = sapply(days, function(d) sum(d >= df$admitDate & d <= df$dcDate)),
  Patients = sapply(days, function(d)
        toString(df$Unit.Number[d >= df$admitDate & d <= df$dcDate]))
)

以下是发生的事情：

> days <- seq(min(df$admitDate), max(df$dcDate), "day")
Error in seq.int(0, to0 - from, by) : 'to' cannot be NA, NaN or infinite
> no.patients <- data.frame(Date = d, 
+                           Num = sapply(days, function(d) sum(d >= df$admitDate & d <=         df$dcDate)))
Error in data.frame(Date = d, Num = sapply(days, function(d) sum(d >=  : 
object 'd' not found

然后，我想也许我需要摆脱NA。所以这就是我所做的：

> df <- df[rowSums(is.na(df)) < 0, ]

再次尝试。这是我得到的：

> days <- seq(min(df$admitDate), max(df$dcDate), "day")
Error in seq.int(0, to0 - from, by) : 'to' cannot be NA, NaN or infinite
In addition: Warning messages:
1: In min.default(numeric(0), na.rm = FALSE) :
no non-missing arguments to min; returning Inf
2: In max.default(numeric(0), na.rm = FALSE) :
no non-missing arguments to max; returning -Inf
> no.patients <- data.frame(Date = d, 
+                           Num = sapply(days, function(d) sum(d >= df$admitDate & d <=   df$dcDate)))
Error in data.frame(Date = d, Num = sapply(days, function(d) sum(d >=  : 
object 'd' not found

Answer 1

试试这个：

days <- seq(min(df$admitDate), max(df$dcDate), "day")
no.patients <- data.frame(
      Date = days, 
      Num = sapply(days, function(d) sum(d >= df$admitDate & d <= df$dcDate)),
      Patients = sapply(days, function(d)
            toString(df$Unit.Number[d >= df$admitDate & d <= df$dcDate]))
)

，并提供：

> head(no.patients)
        Date Num Patients
1 2009-09-19   1  2013459
2 2009-09-20   1  2013459
3 2009-09-21   1  2013459
4 2009-09-22   1  2013459
5 2009-09-23   1  2013459
6 2009-09-24   0

ADDED 患者列表到每一行。修正了df。

的情况

Answer 2

这是另一种方式。这是一个根据进入/退出时间创建队列大小的过程，在这种情况下可用于计算患者数量：

df <- structure(list(Unit.Number = c(2013459L, 2013459L, 2047815L, 
1362858L, 1331174L, 2068040L, 1363711L, 2175972L, 2036695L, 1426614L, 
1403126L, 2083126L, 1334063L, 1349385L, 1404482L, 2175545L, 1296600L, 
1293220L, 1336768L, 2148401L), admitDate = structure(c(14506, 
14633, 14882, 15172, 14945, 15632, 15482, 15601, 16096, 15843, 
16013, 15548, 15436, 15605, 16115, 15597, 15111, 15050, 15500, 
15896), class = "Date"), dcDate = structure(c(14510, 14636, 14886, 
15197, 14951, 15635, 15488, 15603, 16098, 15846, 16016, 15552, 
15438, 15606, 16118, 15598, 15113, 15058, 15501, 15915), class = "Date"), 
los = c(4, 3, 4, 25, 6, 3, 6, 2, 2, 3, 3, 4, 2, 1, 3, 1, 
2, 8, 1, 19)), .Names = c("Unit.Number", "admitDate", "dcDate", 
"los"), row.names = c(NA, 20L), class = "data.frame")

# create dataframe for computing the size of the queue (concurrent patients)
x <- data.frame(date = c(df$admitDate, df$dcDate)
            , op = c(rep(1, nrow(df)), rep(-1, nrow(df)))
            , Unit.Number = c(df$Unit.Number, df$Unit.Number)
            )
# sort and calculate concurrent patients
x <- x[order(x$date), ]  # sort in time order
x$cum <- cumsum(x$op)

# 'x' will have the 'cum' equal to the number of patients concurrently.
# for 'op' == 1, you have the patient ID and 'cum' will be the number of
# patients at that time.

plot(x$date, x$cum, type = 's')

这就是＆＃39; x＆＃39;的第一部分。看起来像：

> head(x,10)
         date op Unit.Number cum
1  2009-09-19  1     2013459   1
21 2009-09-23 -1     2013459   0
2  2010-01-24  1     2013459   1
22 2010-01-27 -1     2013459   0
3  2010-09-30  1     2047815   1
23 2010-10-04 -1     2047815   0
5  2010-12-02  1     1331174   1
25 2010-12-08 -1     1331174   0
18 2011-03-17  1     1293220   1
38 2011-03-25 -1     1293220   0
>

如何识别r中的时间重叠

2 个答案: