以下是从xml文件中获取用户名和密码的代码,但它不会获取数据吗?
private var myXML: XML = new XML();
private function connect(event: Event): void {
var str1: String = username.text.toString();
trace(str1);
var str2: String = password.text.toString();
trace(str2);
var str3: String = myXML.authentication.username;
Alert.show(str3);
var str4: String = myXML.authentication.password;
if (str1 == str3 && str2 == str4) {
Alert.show("sucessfully Connected")
} else {
Alert.show("invalid username password");
}
}
答案 0 :(得分:0)
您为myXML分配数据的位置是什么?
var settingFile:File;
var stream:FileStream;
var resultXML:XML;
settingFile = settingFile.resolvePath("setting.xml");
stream = new FileStream;
if(settingFile.exists)
{
stream.open(settingFile,FileMode.READ);
resultXML = XML(stream.readUTFBytes(stream.bytesAvailable));
stream.close();
var xmlDoc:XMLDocument = new XMLDocument(resultXML.toString());
var decoder:SimpleXMLDecoder = new SimpleXMLDecoder(true);
var resultObj:Object = decoder.decodeXML(xmlDoc);
}
从该结果可以访问用户名和密码
如果您使用的是FlexApplication,则将xml文件转换为xmlDocument并对其进行解码。然后从解码的对象中获取用户名和密码。
var xmlDoc:XMLDocument = new XMLDocument(myXML.toString());
var decoder:SimpleXMLDecoder = new SimpleXMLDecoder(true);
var resultObj:Object = decoder.decodeXML(xmlDoc);
你可以这样试试。
private var myXML: XML = new XML();
private function connect(event: Event): void {
var xmlDoc:XMLDocument = new XMLDocument(myXML.toString());
var decoder:SimpleXMLDecoder = new SimpleXMLDecoder(true);
var resultObj:Object = decoder.decodeXML(xmlDoc);
var str1: String = username.text.toString();
trace(str1);
var str2: String = password.text.toString();
trace(str2);
var str3: String = resultObj.authentication.username;
Alert.show(str3);
var str4: String = resultObj.authentication.password;
if (str1 == str3 && str2 == str4) {
Alert.show("sucessfully Connected")
} else {
Alert.show("invalid username password");
}
}
答案 1 :(得分:0)
为什么不尝试使用URL加载器加载XML文件并捕获COMPLETE事件以获取数据?